REASONING FOR CSIR NET

             Inserting, Missing Term 

                    For CSIR NET

1)

2)

3)

A) 41
B) 72
C) 23
D) 24


4)

5)

6)

7)

8)

9)

Answers with explanation -

1)    (c)
From first fig. 6² + 4²  = 36 + 16 = 52

From 2nd fig. 3² + 5² = 9 + 25 = 34

In the same way
8² + ?² = 68
        ?² = 68 - 64 = 4
         ? = 2
So ans is 2



2).
    4 + 3 = 7;.        7² = 49
    1 + 5 = 6;.         6² = 36
    7 + 5 = 12;       12² = 144
    2 + 8 = 10;       10² = 100.
So ans is 100



3)    (c)
 From first column 10+5+6 = 21;  21 * 2 = 42
 From 2nd column 17+3+14 = 34 ; 34 * 2 = 68
In the same way.   8+5+? = 92 / 2
So ans is 23
     



4).  (c)  225
 From first fig. 2+3+5 = 10;  10² = 100
In the same way 5+6+4 = 15² = 225




5).   (D)
 From fig 1-   10+12+16 = 38
 From fig 2-.  15+21+30 = 66
 From fig 3.    17+?+27 = 81
So ans is 37



6)  (A)
From the fig 2*3= 6;  3*6 = 18 ;
                     6*18= 108 ;  108*18 = 1944
So ans is 1944


7)  (C)
From fig A   3*1+4*2= 11
From fig B.   2*4+5*3 = 23
From fig C    2*5+6*3 = 28
So ans is 28


8).  (C)
From first column 5*3=15
From 2nd column 2*7 = 14
Same way  6*3 = 18



9).  (B)
From  fig 1
3*2=6
2*2=4
1*4=4
No is 644

From fig 2
2*1= 2
2*4=8
3*3=9
No.  is 289
In the same way ans is 798






Click below for last year paper part A

http://ajaytutorialsmathsandscience.blogspot.com/2016/06/csir-net-december-2015-mathematical.html